0.020 kg of ice and 0.10 kg of water at 0 ºC are in a container. Steam at 100 ºC is passed until all the ice is just melted. How much water is now in the container? (Specific latent heat of steam = 2.3 × 10 6 J kg –1 ; latent heat of ice= 3.4 × 10 5 J kg –1 ; specific heat capacity of water = 4.2 × 10 3 J kg –1 ºC –1 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
Sol. Heat needed to melt ice:
Steam needed:
Total water after condensation and melting:
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